求出下列图形中x的值：

求出下列图形中x的值：

$\left ( {1} \right )$$4x+6{0}^{\circ }=\left ( {5-2} \right )\times 18{0}^{\circ }$

$4x+6{0}^{\circ }=54{0}^{\circ }$

$4x={480}^{\circ }$

$x=12{0}^{\circ }$

$\left ( {2} \right )$$3x+4x+3x+2x=36{0}^{\circ }$

$12x=36{0}^{\circ }$

$x=3{0}^{\circ }$

$\left ( {3} \right )$$AB\parallel CD\, $

$\therefore \angle B=18{0}^{\circ }-6{0}^{\circ }=12{0}^{\circ }$

$x+15{0}^{\circ }+6{0}^{\circ }+13{5}^{\circ }+12{0}^{\circ }=\left ( {5-2} \right )\times 18{0}^{\circ }$

$x+{465}^{\circ }=54{0}^{\circ }$

$x={75}^{\circ }$

综上所述，故结论是：

$\left ( {1} \right )$$x=12{0}^{\circ }$

$\left ( {2} \right )$$x=3{0}^{\circ }$

$\left ( {3} \right )$$x={75}^{\circ }$